Question

ABCD is a parallelogram whose height DE is 4cm and base AB is 10cm. if height AF on BC is 5 cm, find width BC

Answer 1

Value of width BC is 8 cm.

Step-by-step explanation:

1. Given data

  ABCD is parallelogram

  AB = 10 cm

  DE is perpendicular to side AB. Where

  DE = 4 cm

  AF is perpendicular to side BC. Where

  AF = 5 cm

2. Area of parallelogram = Side of parallelogram × Altitude on side

   $\mathbf{\textrm{Area of parallelogram}= AF\times BC= AB\times DE}$

 

  $\mathbf{AF\times BC= AB\times DE}$

  Means

  $\mathbf{BC= \frac{AB\times DE}{AF}}$

  $\mathbf{BC= \frac{10\times 4}{5}=8 \ cm}$  

Answer 2

Answer:

1. Given data

ABCD is parallelogram

AB = 10 cm

DE is perpendicular to side AB. Where

DE = 4 cm

AF is perpendicular to side BC. Where

AF = 5 cm \mathbf{\textrm{Area of parallelogram}= AF\times BC= AB\times DE}Area of parallelogram=AF×BC=AB×DE

\mathbf{AF\times BC= AB\times DE}AF×BC=AB×DE

Means

\mathbf{BC= \frac{AB\times DE}{AF}}BC=

AF

AB×DE

\mathbf{BC= \frac{10\times 4}{5}=8 \ cm}BC=

5

10×4

=8 cm