Question

ABCD is a parallelogram with ∠A= 80°. The internal bisectors ∠B and ∠C meet at O. Find the measure of three angles of triangle BCO

Answer 1

Step-by-step explanation:

∠A = 80°

We know that the opposite angles of a parallelogram are equal.

∠A = ∠C = 80°

And

∠OCB = (1/2) × ∠C

= (1/2) × 80°

= 40°

∠B = 180° – ∠A (the sum of interior angles on the same side of the transversal is 180)

= 180° – 80°

= 100°

Also,

∠CBO = (1/2) × ∠B

= (1/2) × 100°

= 50°

By the angle sum property of triangle BCO,

∠BOC + ∠OBC + ∠CBO = 180°

∠BOC = 180° – (∠OBC + CBO)

= 180° – (40° + 50°)

= 180° – 90°

= 90°

Hence, the measure of all the three angles of a triangle BCO is 40°, 50° and 90°.

Answer 2

Answer:

Perfect in the 5 square root the c and b can’t touch to which means you have to multiply 80 and O which will get you answer  127°

Step-by-step explanation: