ABCD is a parallelogram with AD parallel to BC. if R is any point on AD, then find the area of triangle BRC.
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Answered by
2
Answer:
Step-by-step explanation:
Since AD||BC
According to Therom.
Any point on a parallelogram which is on its parallel side and form triangle equal to half of area of parallelogram
Area of parallelogram= base ×
Height
Therefore area of triangle is
1/2 ×base xheight Ans
Step-by-step explanation:
Since AD||BC
According to Therom.
Any point on a parallelogram which is on its parallel side and form triangle equal to half of area of parallelogram
Area of parallelogram= base ×
Height
Therefore area of triangle is
1/2 ×base xheight Ans
Answered by
2
Solution:
Draw a line RS from point R & perpendicular to the line BC meeting at point S on BC (as shown in fig.).
Area of Parallelogram ABCD = Base × Height
= BC × RS
Also area of Triangle BRC = 1/2 × Base × Height
=1/2 × BC × RS
Therefore, from the above conditions the area of Triangle BRC = 1/2 × Area of Parallelogram ABCD.
Hope you got it!
Draw a line RS from point R & perpendicular to the line BC meeting at point S on BC (as shown in fig.).
Area of Parallelogram ABCD = Base × Height
= BC × RS
Also area of Triangle BRC = 1/2 × Base × Height
=1/2 × BC × RS
Therefore, from the above conditions the area of Triangle BRC = 1/2 × Area of Parallelogram ABCD.
Hope you got it!
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