Question

ABCD is a parallelogram with angle A = 70°. The bisectors of angle B and angle C meet at P inside the parallelogram. Find the measure of angle BPC. Explain it properly and fast please.Its urgent​

Answer 1

Answer:

Hi dear the answer is A=70 , BC=70 140 and the degree 180

Step-by-step explanation:

180,140

180-140=40

is the answer dear I explained in easy it is ok for you

Answer 2

$\huge\mathfrak{Bonjour!!}$

$\huge\fcolorbox{black}{aqua}{Solution:-}$

✒ ᴀɴsᴡᴇʀ:-

⛄ Angle BPC = 90°

✒ sᴛᴇᴘ-ʙʏ-sᴛᴇᴘ ᴇxᴘʟᴀɴᴀᴛɪᴏɴ:-

⛄ɢɪᴠᴇɴ:-

★ ᴀʙᴄᴅ ɪs ᴀ ᴘᴀʀᴀʟʟᴇʟᴏɢʀᴀᴍ

★ ʙɪsᴇᴄᴛᴏʀs ᴏғ ᴀɴɢʟᴇ ʙ ᴀɴᴅ ᴄ ᴍᴇᴇᴛ ᴀᴛ ᴀ ᴘᴏɪɴᴛ ᴘ.

⛄ ᴛᴏ ғɪɴᴅ:-

★ ᴀɴɢʟᴇ ʙᴘᴄ

⛄sᴏʟᴜᴛɪᴏɴ:-

★ sɪɴᴄᴇ ᴀʙᴄᴅ ɪs ᴀ ᴘᴀʀᴀʟʟᴇʟᴏɢʀᴀᴍ, ᴛʜᴇʀᴇғᴏʀᴇ ɪᴛs ᴏᴘᴘᴏsɪᴛᴇ ᴀɴɢʟᴇs ᴀʀᴇ ᴇϙᴜᴀʟ.

∴ ᴀɴɢʟᴇ ᴅᴀʙ = 70° = ᴀɴɢʟᴇ ᴅᴄʙ

ɴᴏᴡ,

ᴀɴɢʟᴇ ᴘᴄʙ = 70°/2 = 35° ( ∵ ᴄᴘ ʙɪsᴇᴄᴛs ᴀɴɢʟᴇ ᴄ)

ᴀʟsᴏ,

ᴀɴɢʟᴇ ᴅᴀʙ + ᴀɴɢʟᴇ ᴀʙᴄ = 180° ( ∵ ᴀᴅᴊᴀᴄᴇɴᴛ ᴀɴɢʟᴇs ᴀʀᴇ sᴜᴘᴘʟᴇᴍᴇɴᴛᴀʀʏ ɪɴ ᴀ ᴘᴀʀᴀʟʟᴇʟᴏɢʀᴀᴍ)

⇒ 70° + ᴀɴɢʟᴇ ᴀʙᴄ = 180°

⇒ᴀɴɢʟᴇ ᴀʙᴄ = 110°

⇒ᴀɴɢʟᴇ ᴘʙᴄ = 110°/2 = 55° ( ∵ ᴘʙ ʙɪsᴇᴄᴛs ᴀɴɢʟᴇ ʙ)

ɴᴏᴡ,

ᴄᴏɴsɪᴅᴇʀ ∆ᴘʙᴄ.

ʜᴇʀᴇ,

ᴀɴɢʟᴇ ᴘʙᴄ + ᴀɴɢʟᴇ ʙᴘᴄ + ᴘᴄʙ = 180° ( ᴀɴɢʟᴇ sᴜᴍ ᴘʀᴏᴘᴇʀᴛʏ ᴏғ ᴀ ᴛʀɪᴀɴɢʟᴇ)

⇒ 55° + ᴀɴɢʟᴇ ʙᴘᴄ + 35° = 180°

⇒ 90° + ᴀɴɢʟᴇ ʙᴘᴄ = 180°

⇒ ᴀɴɢʟᴇ ʙᴘᴄ = 90°

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