ABCD is a parallelogram with angleA = (4x+15 )° and angleC = (5x+4)° . Find angleA.
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Answered by
2
Answer:
m∠A = 59°
Step-by-step explanation:
In parallelogram ABCD
m∠A ≅ m∠C i [ Opposite angles of parallelogram are congruent ]
( 4x + 15 )° = ( 5x + 4 )° [ Given ]
4x + 15 = 5x + 4
4x - 5x = 4 - 15
-x = -11
∴ x = 11
∴ m∠A = 4(11) + 15
= 44 + 15
m∠A = 59°
∴ m∠C = 59° [ from i ]
ImaanAli7856:
Thanks your answer is right.
Is answer me ye i or m ka Marland kya hai
Sorry Marland nahi matlab
i - is like.......ham jo nam dete he na equation ko eg. 1,2,3
aur m∠A is measure of angle A
Ok
Answered by
1
In a parallelogram opposite angle sum = 180
A + C = 180
4x + 15 + 5x + 4 = 180
9x+ 19 =180
9x = 180-19
9x = 171
x = 171÷9
x = 19
angle A =4x+ 15
=4×19 + 15
=76+15
=91
adjacent angles of a parallelogram are supplementary, and not opposite angles.
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