Question

ABCD is a parallelogram with area 252 sq CM. P is any point on segment AB such that PA:PB=1:2.Find A ( APD)

Answer 1

AB=AP:PB=1:2
AP=X PB=2X
AB=3X
area =b×h 252=3x×h 252÷3=x×h 84=x×h
A(APD)=x×h=84

Answer 2

Answer:  Area of APD is 84 cm².

Step-by-step explanation:

Since we have given that

ABCD is a parallelogram.

Ar(ABCD) = 252 sq. cm

Since P is any point on segment AB such that PA: PB = 1:2

So, We know that ,

$\frac{ar(ABCD)}{ar(APD)}=\frac{AB}{PA}=\frac{1+2}{1}=\frac{3}{1}\\\\ar(APD)=\frac{1}{3}(ar(ABCD))\\\\ar(APD)=\frac{1}{3}\times 252\\\\ar(APD)=84\ cm^2$

Hence, Area of APD is 84 cm².