Question

ABCD is a parallelogram with sides AB=12cm, BC=10cm and diagonal AC= 16cm. Find the area of the parallelogram. Also find the distance between it's shorter sides.
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Answer 1

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Answer 2

Let slant height =16

Then then angle is sin65degrees=h/16

16*sin65degrees= h/16*16

h=14.5cm

When opp sides of parallelogram are same

Let the base CD=12cm

Area of parallelogram =Base *Height

A=B*H

A=12*14.5cm

A=174cm