Math, asked by pritikavyaarora, 6 hours ago

ABCD is a parallelogrm where angle A = 3x-2 and angle B = 2x-3 find the value of x​

Answers

Answered by Anonymous
5

Answer:

Interior angles on the same side of the transversal are supplementary.

∠A+∠B=180

o

⇒(3x+2)

o

+(2x−32)

o

=180

o

⇒3x+2+2x−32=180

o

⇒5x−30=180

o

⇒5x=210

⇒x=42

o

Thus, ∠A=3x+2=3×42

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+2=128

o

∠B=2x−32=2×42

o

−32=52

o

Also, opposite angles of a parallelogram are congruent.

∠A=∠C=128

o

∠B=∠D=52

o

Answered by kawaljeetsarna
2

Step-by-step explanation:

in a parellelogram the adjacent angles have a sum of 180°

so angle A +angle B = 180°

3x-2+2x-3=180

5x-5=180

5x= 175

x= 35

angle A= 3x35-2=103

angle B=2x35-3=67

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