Question

ABCD is a paralleogram.AC is the diagonal.prove that​

Answer 1

Step-by-step explanation:

Given is a rhombus ABCD & ∠BAC=38

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We know that all sides of a rhombus are equal.

So AB=BC=CD=DA

In isosceles △ ABC,

∠BAC=∠BCA=38

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[ Base angles are equal in isosceles triangle ]

Again in isosceles triangle ABC,

∠BAC+∠BCA+∠ABC=180

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⇒∠ABC=180

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−38

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−38

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⇒∠ABC=180

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−76

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⇒∠ABC=104

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We know that Opposite angles of a rhombus have equal measure.

So ∠ABC=∠ADC

Therefore ∠ADC=104

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