ABCD is a paralleogram whose diagonals interdect each other at right angle .if the length of the diagonals is 6 cm and 8cm find the length of all the sides of the parallelogram.
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Parallelogram whose diagonals intersect each other at right angle is a Rhombus
so length of All sides are equal
Let O is the point of intersection
So,
AB² = AO² + BO² (Triangle AOB is right angled at O)
AB² = (6/2)² + (8/2)² = 3² + 4²
AB² = 9 + 16 = 25
AB = √25 = ±5
AB≠ -5 (Because length cannot be negative)
Hence AB = 5
So, all the sides are :
AB = 5cm
BC = 5cm
CD = 5cm
AD = 5cm
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