ABCD is a parellelogram B-114°, ACD=36° LPAB=(2y+10)
and ACB = 36°.Find x and y
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Let ABCD is a ∥gm in which AB=CD=2x, then AP=PB=x, because P is mid point. Draw DE⊥AB=h
or APCD=36cm2⇒21(x+2x)h=36⟶(1)
ar △ABC=21h×2x=hx⟶(2)
21×3x×h=36⇒hx=24(from eq(1))
Hence, ar △ABC=hx=24cm2
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