Question

abcd is a parllelogram. ab is produced to e so that be=ab. prove that ed bisects bc​

Answer 1

Answer:

ABCD is a parallelogram.

BE = AB

To show,

ED bisects BC

Proof:

AB = BE (Given)

AB = CD (Opposite sides of ||gm)

∴ BE = CD

Let DE intersect BC at F.

Now,

In ΔCDO and ΔBEO,

∠DCO = ∠EBO (AE || CD)

∠DOC = ∠EOB (Vertically opposite angles)

BE = CD (Proved)

ΔCDO ≅ ΔBEO by AAS congruence condition.

Thus, BF = FC (by CPCT)

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Step-by-step explanation:

Answer 2

Answer:

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