Abcd is a parrallelogram and x and y points on the diagonal B D such that DX=BY. Prove that. 1.Ax=cy
2. Triangle AYB congruent triangle CXd
3.Triangle axd congruent triangle cyb
4.AY=CX
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1. In ∆CBY and ∆ADX
CB = AD (Opp sides of //gm)
Angle CBY = Angle ADX ( Opp angles of //gm bisected by diagonal BD)
BY = DX (Given)
Therefore, ∆CBY is congruent to ∆ADX
CY = AX ( corresponding sides of corresponding angles)
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