Question

ABCD is a parrallelogram in which angle A = 75 find the measure of each of the angles B, C AND D

Answer 1

sum of adjacent angles of a parallelogram is 180°

therefore, angle a + angle b = 180°

Step-by-step explanation:

Let angle b be X

=>75°+X =180°

=>X=180°-75°

=>X=105°

now angle b is 105°

angle b =angle c=105°[opposite angles of a parallelogram are equal]

angle a=angle d =75°[opposite angles of a parallelogram are equal]

therefore the angles are 105°,75°,105°,75°

Answer 2

$\huge\red{\underline{\underline{given : }}}$

ABCD is a ||gm in which angle A=75°.

$\huge\green{\underline{\underline{to \: find : }}}$

Angle B, angle C and angle D.

$\huge\blue{\underline{\underline{solution : }}}$

angle C = angle A [•°•opposite angles of the same parallelogram are equal ]

•°• angle C = 75°

as we know the sum of all angles in a quadrilateral is 360°,

•°•we can write:

⇒angle A + angle B + angle C + angle D = 360°

⇒75°+75°+/_C+/_D=360°

⇒150°+/_C+/_C=360° [•°•/_C=/_D]

⇒2/_C=360°-150°

⇒2/_C=210°

⇒/_C=210÷10

⇒/_C=21°

NOTE: /_ denotes angle .

HOPE U GOT IT !!!

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