ABCD is a prallelogram gram whose diagnol intersect at O .if A = (-5,-6) and o (2,-3) then coordinate of c are
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Step-by-step explanation:
Let co-ordinates of C be (x,y), co-ordinates of A (-5,-6) = (x1,y1) and co-ordinates of O (2,-3) = (x2,y2)
In parellelogram ABCD,
AC is a diagonal,
BD and AC intersect at O --> given
∴AO=OC -->Diagonals of parellelogram intersect each other in half
∴Using midpoint forumula:-
x2 = (x1 + x)/2 --> Equation 1
y2 = (y1+y)/2 --> Equation 2
In equation 1,
2 = (-5+x)/2
∴-5+x=4 ∴x=4+5
x=9
In equation 2,
-3 = (-6 + y)/2
∴-6 = -6 + y
y=0 (∵ -6+6=y)
∴The co-ordinates of point C are (9,0)
Hope this helps you
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