ABCD is a quad. whose diagonals are equal and bisect each other at right angles.Prove that ABCD is a square.
nishavini:
pls ans
Answers
Answered by
1
Answer of this question is given in this photo.
Attachments:
THANKS MISS,HOW CAN WE POST DIAGRAM QS?
Answered by
1
As diagnols of ABCD bisect each other, so ABCD is a parallelogram. (Theorem)
Now ABCD is a parallelogram whose diagnols bisect at 90 degree hence it is a rhombus. (Theorem)
Now ABCD is a Rhombus whose diagnols are equal hence it is a square (theorem)
Hence proved
Now ABCD is a parallelogram whose diagnols bisect at 90 degree hence it is a rhombus. (Theorem)
Now ABCD is a Rhombus whose diagnols are equal hence it is a square (theorem)
Hence proved
THANKS,HOW CAN WE POST DIAGRAM QUESTIONS?
Similar questions