Math, asked by tejasviprasanna, 11 months ago

abcd is a quadilateral in which ad =bc . if p q r s are the midpoints of sides ab, ac , cd ,bd show that pqrs is a rhombus

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Answered by robert19991
0

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ABCD is Rectangle in which P,Q,R,S is a mid point . show that PQRS is rhombus.

sr  || ac  \: sr = 1\%2ac \:  \: by \: mid \: point \: theoram \\  \:  \:  \:  \:  \:  \:  \: ...1 \\ pq || ac  \: pq = 1\%2ac \: \: by \: mid \: point \: theorm \\  \:  \:  \:  \:  \:  \:  \: .....2 \\ from \: equation \: 1 \: and \: 2 \\ pqrs \: is \: a \:  || gm

sp || db  \:  \: \: sp = 1\%2db \:  \:  \:  \: by \: mid \: point \: theoram

As we all know that diagonals of rectangle are equal

AB=DB

1%2AC=1%2DB

PQ=SP From equation 2 and 3

ABCD is parallelogram in which adjacent side equal equal so that PQRS is rhombus

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