abcd is a quadilateral with side AB=Cd and AD=BC show that it is a parallelogram?
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Step-by-step explanation:
As the opposite angles of quadrilateral ABCD are equal, i.e., ∠DAB=∠BCD and ∠ABC=∠CDA , so we can say that quadrilateral ABCD is a parallelogram
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Given:In □ABCD
AB=DCandAD=BC
To prove: ABCD is a parallelogram
Construction: Draw diagonal AC and DB.
Proof: in △ABC and △ADC
AD=BC [Given]
AB=DC [Given]
AC=AC [Common side]
∴ By SSS property
△ADC≅△ACB
∴∠DAC=∠DCA
∴AB∣∣DC [By theorem]
In△ABDand△DCB
DB=DB [Common side]
AD=BC [Given]
AB=DC [Given]
∴△ABD≅△DCB
∴AD∣∣BC
Since AB∣∣DC and AD∣∣BC.
△ABCD is parallelogram..
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