ABCD is a quadrilateral A line through D parallel to AC meets BC produced in P .Prove that ar(ABP) =ar (quad ABCD)
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solu:- Given:- ABCD is quadrilateral A line through D parallel to AC meets BC produced in P.
Prove that:- ar (ABP) = ar (quad ABCD)
Proof:- Since, In ∆APC and ∆ADC are lie on the same base AC and between the same parallel line AD and CP.
So, ar (APC) = ar (ADC)
By adding both sides ∆ABC ------ (1)
so, we get , ar (APC) + ar (ABC)=ar (ADC) + ar (ABC)
ar (ABP) = ar (quad ABCD)
Hope it is helpful to you....
Mark as ***Brainlist ***Answer
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Prove that:- ar (ABP) = ar (quad ABCD)
Proof:- Since, In ∆APC and ∆ADC are lie on the same base AC and between the same parallel line AD and CP.
So, ar (APC) = ar (ADC)
By adding both sides ∆ABC ------ (1)
so, we get , ar (APC) + ar (ABC)=ar (ADC) + ar (ABC)
ar (ABP) = ar (quad ABCD)
Hope it is helpful to you....
Mark as ***Brainlist ***Answer
--------_----------_-----------_---------_--------
Kunalno1:
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