ABCD is a quadrilateral all sides of quadrilateral touches to circle . if AB=8 , BC=6 , AD=5 then find length of Cd
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Sol :Let P,Q,R,S be the points where the circle touches the quadrilateral .From a point out side of the circle the two tangents to the circle are equal.AP = AS,BP = BQ , CR = CQ , and DR = DSAdding AP + BP + CR + DR = AS + BQ + CQ + DSAB + CD = AD + BC8 + CD= 5 + 6CD = 3 cm .
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Sol :Let P,Q,R,S be the points where the circle touches the quadrilateral .From a point out side of the circle the two tangents to the circle are equal.AP = AS,BP = BQ , CR = CQ , and DR = DSAdding AP + BP + CR + DR = AS + BQ + CQ + DSAB + CD = AD + BC8 + CD= 5 + 6CD = 3 cm .
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