Question

abcd is a quadrilateral and ac is one of its diagonals prove that ab+bc+cd is greater than da

Answer 1

In ∆ABC,

AB + BC > AC (Sum of any two sides of a triangle is greater than the third side)

Adding CD to both sides, we get

AB + BC + CD > AC + CD … (1)

In ∆ACD,

AC + CD > AD … (2) (Sum of any two sides of a triangle is greater than the third side)

From (1) and (2), we get

AB + BC + CD > AD

Answer 2

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