Math, asked by ravneet85, 1 year ago

ABCD is a quadrilateral and BD is one of its diagonal show that ABCD ia a parallelogram and find its area (diagram of this ques. is in picture) answer with solvation plzzz

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Answered by anandtiwari0019
3
HEY . HERE IS YOUR ANSWER
ABD=90°(Triangle)
2 TRAINGLES ARE THERE
1=ABD
2=CDB
SO AREA = AREA OF ABD+ AREA OF CDB
TOTAL AREA =1/2*5*4+1/2*5*4
AREA=10+10
AREA=20cm^2
HOPE IT HELPS
Answered by deepakkumarpatro
2

Answer:


Step-by-step explanation:

Area of Triangle = (1/2) * Base * Height

Area of Triangle ABD = 10 cm square

Area of Triangle BCD = 10 cm square

Area of Parallelogram = 20 cm square.


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