Question

abcd is a quadrilateral and bd is one of the diagonal as shown .show that abcd is a parallelogram and find its area

Answer 1

Here , ∠ ABD = ∠ CDB = 90°

If we take two lines AB and CD and BD as transversal line , So ∠ ABD and ∠ CDB are interior alternate angles .

And these angles are equal ( As given ∠ ABD = ∠ CDB = 90° ) only when AB | | CD . So

AB | | CD

And

AB = CD = 3 cm

We know if in a quadrilateral a pair of sides are equal and parallel to each other so that quadrilateral is a parallelogram .

So,

ABCD is a parallelogram ( Hence proved )

We know area of parallelogram = Base × Height , So

Area of parallelogram ABCD = AB × BD = 3 × 4 = 12 cm2 ( Ans )

Hope this information will clear your doubts about Areas of Parallelograms and Triangles.

ples mark my answer as a brainliest!

Answer 2

Answer:

area is 12cm^2 ..............