ABCD is a quadrilateral. AO and BO are the angle bisectors of angle A
and B which meet at O. If ZC = 70°, ZD = 50°, find ZAOB.
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We have,
ABCD is a quadrilateral.
Given that,
∠C=70 ,∠D=50
So, ∠A+∠B+∠C+∠D=360
(A+B)=360 −(C+D)
⇒(A+B)=360 −(70) +50)
⇒(A+B)=360 −120
⇒(A+B)=240
According to given question,
∠OAB= 2 ∠A
∠OAB= 2 ∠B
Now,
∠OAB+∠OBA= 2
∠A+∠B =120
⇒∠AOB+120=180
⇒∠AOB=180 −120 ⇒∠AOB=60
Hence, this is the answer.
Hope this helps!
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