Question

ABCD is a quadrilateral.AO And BO are the angle bisectors of angle A And B which meet at O.IF angle C=70°,angle D=50°,find angle AOBpls with solve​

Answer 1

Answer:

We have, ABCD is a quadrilateral. Given that, C = 70^o, D = 50^o So, A + B + C + D = 360^o ( A + B ) = 360^o - ( C + D ) ( A + B ) = 360^o - ...

Answer 2

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ABCD is a quadrilateral. AO And BO are the angle bisectors of angle A and B which meet at O. If angle C=70°, angle D=50°, find angle AOB.

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ĞIVĔN:-

● ABCD is a quadrilateral

● AO And BO are the angle bisectors of angle A and B which meet at O

● ∠C = 70° and ∠D = 50°

TØ FINĐ:-

● ∠AOB

ŠØLUŤION:-

∠A + ∠B + ∠C + ∠D = 360°

let ∠A and ∠B be x

so,

⇒ x + x + 70° + 50° = 360°

⇒ 2x + 120° = 360°

⇒ 2x = 360 - 120

⇒ x = 240/2

⇒ x = 120°

AO And BO are the angle bisectors of angle A and B

so,

∠A = 120/2 = 60°

∠B = 120/2 = 60°

Now,

In triangle AOB,

⇒ ∠AOB + ∠OAB + ∠OBA = 180°

⇒ ∠AOB + 60° + 60° = 180°

⇒ ∠AOB + 120° = 180°

⇒ ∠AOB = 180 - 120

⇒ ∠AOB = 60°

Hence, ∠AOB = 60°

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