Question

ABCD is a quadrilateral
, find the values of x,y and z

Answer 1

Answer:

Answer

From the figure

AD∥BC,BD is the transversal line

⟹∠ADB=∠DBC (∵alternate angles)

⟹z=30

∘

Also

100

∘

,x are supplementary angles

So x=180

∘

−100

∘

=80

∘

x,y,30

∘

forms a triangle

⟹x+y+30

∘

=180

∘

⟹y=180

∘

−80

∘

−30

∘

=70

∘

Answer 2

Answer:

60 degrees

Step-by-step explanation:

I will definitely help you with this question.

answer=  y=60degrees

as by the prop. of linear pair

120+y=180

y=180-120

y=60degrees

by prop. of interior angles of a quad. (its sum is 360 degrees)

70+80+60+x=360

210+x=360

x=360-210

x=150 degrees

thank you