Question

ABCD is a quadrilateral, in which 2 sides AD = BC, and P, Q, R, & S are the mid-points of side AB, diagonal AC, side CD & diagonal BD.
Prove that the PQRS is a Rhombus.

(This is a rough figure made by myself)​

Answer 1

if AD=BC then the quadrilateral ABCD is parallelogram. (opposite sides of parallelogram are congruent.)

then prove it by the property of midpoints, parallelogram & rhombus (by the same property of both of them)

Answer 2

Answer:

is your answer friend

Step-by-step explanation:

thanks