ABCD IS A QUADRILATERAL IN WHICH AB=AD,
ANGLE A =ANGLE C=90°
BC =8CM
SD=6CM
FIND AB AND CALCULATE THE AREA OF TRIANGLE ABD
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Answer:
Hence the length of AB is 5√2cm
Step-by-step explanation:
Given AB=AD,A=90°=C,BC=8 cm and CD=6 cm
BCD is a right triangle.
BD
2
=BC
2
+DC
2
[Pythagoras theorem]
BD
2
=8
2
+6
2
BD
2
=64+36
BD
2
=100
Taking square root on both sides,
BD=10cm
ABD is a right triangle.
BD
2
=AB
2
+AD
2
[Pythagoras theorem]
10
2
=2AB
2
[∵AB=AD]
100=2AB
2
AB
2
=100/2
AB
2
=50
Taking square root on both sides,
AB=√50
AB=√(2×25)
AB=5√2cm
Hence the length of AB is 5√2cm.
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