ABCD is a quadrilateral in which AB=BC and AD=CD
Show that BD bisects both the angles ABC and ADE
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◆Ekansh Nimbalkar◆
hello friend here is your required answer
hello friend here is your required answer
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Hey there !
IN ΔABD and ΔCBD ,
AD = CD [ given ]
BD = BD [ Common ]
AB = BC [ given ]
ΔABD ≅ ΔCBD [ SSS ]
∠ABD = ∠1
∠CBD = ∠2
∠1 =∠2 [ CPCT ]
Also ,
∠3 = ∠4 [ CPCT ]
Hence ,
BD bisects both the angles ABC and ADE
IN ΔABD and ΔCBD ,
AD = CD [ given ]
BD = BD [ Common ]
AB = BC [ given ]
ΔABD ≅ ΔCBD [ SSS ]
∠ABD = ∠1
∠CBD = ∠2
∠1 =∠2 [ CPCT ]
Also ,
∠3 = ∠4 [ CPCT ]
Hence ,
BD bisects both the angles ABC and ADE
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