abcd is a quadrilateral in which ab=cd and ad=cb show that it is aparallelogram
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In quadrilateral ABCD
we have
AB = CD
and
AD = BC
Now join segment
A and C
Now in
ΔABC
and
ΔACD
we have
AB = CD ----- already given
AD = BC ----- already given
and
AC = AC ----- common
Hence
ΔABC ≈ ∆ ACD
∴ <DAC = <BCA - opposite sides are equal
DC and AB
∴
CD || AB - as alternate angles are equal
∴ <DCA = <CAB - opposite sides are equal
AD and BC
∴ AD || BC - as alternate angles are equal
As opposite sides of quadrilateral are parallel,
ABCD is a parallelogram.
we have
AB = CD
and
AD = BC
Now join segment
A and C
Now in
ΔABC
and
ΔACD
we have
AB = CD ----- already given
AD = BC ----- already given
and
AC = AC ----- common
Hence
ΔABC ≈ ∆ ACD
∴ <DAC = <BCA - opposite sides are equal
DC and AB
∴
CD || AB - as alternate angles are equal
∴ <DCA = <CAB - opposite sides are equal
AD and BC
∴ AD || BC - as alternate angles are equal
As opposite sides of quadrilateral are parallel,
ABCD is a parallelogram.
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