ABCD is a quadrilateral in which AB||DC and AD||BC.find angle b,c,d and angle a=50°
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Since two pairs of opposite sides are equal (as given AB ║ DC and AD ║ BC)
⇒ the given quadrilateral is a parallelogram
Since opposite angles of a parallelogram are equal
⇒ ∠a = ∠c = 50°
similarly ∠d = ∠b , let it be equal to x .
Then the sum of all the angles of a quadrilateral is equal to 360°
⇒ ∠a + ∠b + ∠c + ∠d = 360°
⇒ 50° + x + 50° + x = 360 °
⇒ 100° + 2x = 360 °
⇒ 2x = 360 - 100
⇒ 2x = 260
⇒ x = 130°
⇒ ∠ b = ∠d = 130°
⇒ the given quadrilateral is a parallelogram
Since opposite angles of a parallelogram are equal
⇒ ∠a = ∠c = 50°
similarly ∠d = ∠b , let it be equal to x .
Then the sum of all the angles of a quadrilateral is equal to 360°
⇒ ∠a + ∠b + ∠c + ∠d = 360°
⇒ 50° + x + 50° + x = 360 °
⇒ 100° + 2x = 360 °
⇒ 2x = 360 - 100
⇒ 2x = 260
⇒ x = 130°
⇒ ∠ b = ∠d = 130°
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a quadrilateral with opposite sides equal is a parallelogram.
so a=c and b=d
and a+b+c+d=360
∴a=c=50 and b=d=180-50=130
so a=c and b=d
and a+b+c+d=360
∴a=c=50 and b=d=180-50=130
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