Abcd is a quadrilateral in which ab // dc and ad//bc prove that angle adc is eaual to angle abc
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Given: ABCD is a quadrilateral in which AB || DC and AD || BC.
Since DC || AB,
∴ ∠CDA + ∠DAB = 180° ......(1) (Interior angle on the same side of the transversal AD)
Also, AD || BC,
∴ ∠DAB + ∠ABC = 180° ......(2)
Equating equation (1) and (2),
∠CDA + ∠DAB = ∠DAB + ∠ABC
⇒ ∠CDA = ∠ABC
Since DC || AB,
∴ ∠CDA + ∠DAB = 180° ......(1) (Interior angle on the same side of the transversal AD)
Also, AD || BC,
∴ ∠DAB + ∠ABC = 180° ......(2)
Equating equation (1) and (2),
∠CDA + ∠DAB = ∠DAB + ∠ABC
⇒ ∠CDA = ∠ABC
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