ABCD is a quadrilateral in which AB parallel to CD and AD=BC=5 if
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Answered by
1
Given: ABCD is a quadrilateral in which AB parallel to CD and AD=BC=5 if ∠A=105º
We need to find the value of ∠B
Solution:
From the properties of a parallelogram, we know that
Vertically opposite angles are equal.
Hence ∠A and ∠B forms Co interior angles and the sum of Co interior angles is 180º
∠A + ∠B= 180º
105 +∠B =180º
∠B=180º-105º
∠B=75º
Answered by
4
Given:ABCD is a quadrilateral in which AB parallel to CD and AD=BC=5 if ∠A=105º
We need to find the value of ∠B
Solution:
From the properties of a parallelogram, we know that
Vertically opposite angles are equal.
Hence ∠A and ∠B forms Co interior angles and the sum of Co interior angles is 180º
∠A + ∠B= 180º
105 +∠B =180º
∠B=180º-105º
∠B=75º
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