ABCD is a quadrilateral in which AD=BC and angle DAB=angle CBA.Prove that BD=AC
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Answered by
19
Given: AD=BC, angle DAB= angle CBA
To Prove: Δ ABD ≅ Δ BAC, BD = AC, ∠ ABD = ∠ BAC
Proof: In triangle ABD and Triangle BAC,
AD = BC (given)
∠ DAB = ∠ CBA (given)
AB = BA (common)
therefore, Δ ABD ≅ Δ BAC (SAS rule)
BD = AC (CPCT)
∠ ABD = ∠ BAC (CPCT)
Hence Proved
To Prove: Δ ABD ≅ Δ BAC, BD = AC, ∠ ABD = ∠ BAC
Proof: In triangle ABD and Triangle BAC,
AD = BC (given)
∠ DAB = ∠ CBA (given)
AB = BA (common)
therefore, Δ ABD ≅ Δ BAC (SAS rule)
BD = AC (CPCT)
∠ ABD = ∠ BAC (CPCT)
Hence Proved
Answered by
6
see that picture and you will get the answer
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