Math, asked by kuruvalokesh8750, 6 months ago

ABCD is a quadrilateral in which AD= BC and angle DAB= angle CBA prove that (i) BD = AC (ii) angle ABD = angle BAC ​

Answers

Answered by Anonymous
1

Answer:

Congruence of triangles:

Two ∆’s are congruent if sides and angles of a triangle are equal to the corresponding sides and angles of the other ∆.

 

In Congruent Triangles corresponding parts are always equal and we write it in short CPCT i e, corresponding parts of Congruent Triangles.

 

It is necessary to write a correspondence of vertices correctly for writing the congruence of triangles in symbolic form.

 

Criteria for congruence of triangles:

There are 4 criteria for congruence of triangles.

SAS( side angle side):

Two Triangles are congruent if two sides and the included angle of a triangle are equal to the two sides and included angle of the the other triangle.

----------------------------------------------------------------------------------------------------

First use, SAS rule to show congruence of triangles and then use CPCT to show ii & iii parts.

Given:

In quadrilateral ABCD,

AD = BC &

∠DAB = ∠CBA

 

To Prove:

(i)              ΔABD ≅ ΔBAC

(ii)            BD=AC

(iii)           ∠ABD = ∠BAC

 

Proof:

i)

In ΔABD & ΔBAC,

AB = BA    (Common)

∠DAB = ∠CBA  (Given)

AD = BC (Given)

Hence, ΔABD ≅ ΔBAC.        

( by SAS congruence rule).

(ii) Since, ΔABD ≅ ΔBAC

Then, BD = AC                                       ( by CPCT)

(iv)   Since, ΔABD ≅ ΔBAC

Then , ∠ABD = ∠BAC                         (by CPCT)

=========================================================

Hope this will help you.....

Step-by-step explanation:

Answered by prabhas24480
0

Answer:

given:AD=BC

angleDAB=angleCBA

to prove:triangleABD congurent. triangleBAC

:BD=AC

:angleABD=angleBAC

proof:AD=BC (given)

DAB=CBA (given)

AB=AB (common)

therefore triangleABD congurent triangleBAC

BD=AC (cpct)

angleABD=angleBAC (cpct)

Similar questions