Question

ABCD is a quadrilateral in which AD=BC and angle DBA=angle CBA prove that 1.∆ABD=~∆BAC. 2.BD=AC. 3.angle ABD=angle BAC​

Answer 1

Answer:-

$⇒\text{AB = BA (common side) }$

$⇒\text{∠DAB = ∠CBA \: \: \: \: \: \: \: \: \: \: \: (Given)}$

$⇒\text{AB = BC (Given)}$

So,

$⇒\text{∆ABD } \cong \: \text{∆BAC \: ( by SAS Rule)}$

$⇒\text{BD = AC (congruency)}$

$\text{∠ABD =∠BAC \: \: \: \: \: \: (congruency)}$

$\\ \\ \\ \\ \sf \colorbox{lightgreen} {\red★ANSWER ᵇʸɴᴀᴡᴀʙ⌨}$

Answer 2

Answer:

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