ABCD is a quadrilateral in which AD = BC. If P, Q, R, S be the mid points of AB, AC, CD and BD respectively, show that PQRS is a rhombus.
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First of all we will draw a quadrilateral ABCD with AD = BC and join AC, BD, P,Q,R,S are the mid points of AB, AC, CD and BD respectively.
In the triangle ABC, P and Q are mid points of AB and AC respectively.
PQ || BC and PQ = 1/2
BC .. (1)
In ΔADC, QR = 1/2
AD = 1/2
BC ... (2)
Now we will consider ΔBCD,
SR = 1/2
BC.. (3)
In ΔABD,
PS = 1/2
AD = 1/2
BC.. (4)
So from (1), (2), (3) and (4)
we will get
PQ = QR = SR = PS
All sides are equal so PQRS is a Rhombus.
If there is any confusion please leave a comment.
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