ABCD is a quadrilateral in which all the four angles, A = B and C=D. Show that AB||DC.
Answer me fast.
[Notice: Don't spam otherwise I will report him]
Answers
Answer:
Solution:-
Given,
ABCD is a quadrilateral
Angles A=B=Ç=D
To Prove,
AB || CD and AD || BC
Proof:- Here,
angle A+B+Ç+D=360° [angle sum property of quadrilaterals]
=>A+A+A+A=360°
=>4A=360°
=>A=90° ……[equation 1]
Again, angle A+B=180°
Therefore, angles A and B are linear
And also they are adjacent.
Therefore, AD || BC because there interior angles A and B add up to 180°.
Similarly, angle A+D=180°
Therefore, angles A and D are linear
And also they are adjacent.
Therefore, AB || CD because there interior angles A and B add up to 180°.
Therefore, it is proved that AB ||CD
And AD || BC.
Solution:-
Given,
ABCD is a quadrilateral
Angles A=B=C=D
To Prove,
AB || CD and AD || BC
Proof:-
Here,
angle A+B+Ç+D=360° [angle sum property of quadrilaterals]
A+A+A+A=360°
4A=360°
A=90° ……[equation 1]
Again,
angle A+B=180°
Therefore, angles A and B are linear
And also they are adjacent.
And also they are adjacent.Therefore, AD || BC because there interior angles A and B add up to 180°.
Similarly, angle A+D=180°
Therefore, angles A and D are linear
Therefore, angles A and D are linearAnd also they are adjacent.
Therefore, angles A and D are linearAnd also they are adjacent.Therefore, AB || CD because there interior angles A and B add up to 180°.
Therefore, it is proved that AB ||CD