ABCD is a quadrilateral in which AP and CQ are perpendicular to diagonal BD and AP=CQ.prove that BD bisects AC.
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Answer:
In the given quadrilateral ABCD,
AP and CQ are perpendiculars.
In the triangle APB and triangle CQD,
as,
AB is parallel to CD.
∠ABP = ∠CDQ (Alternate interior angles)
AB = CD (opposite sides of a parallelogram are equal)
and,
∠APB = ∠CQD = 90° (Right Angles)
Therefore,
ΔAPB ≅ ΔCQD (By ASA Congruence)
Hence, Proved.
(ii).
As,
ΔAPB ≅ ΔCQD. So, from the previous part we can say that,
The corresponding sides of the triangle are also equal.
i.e.
AP = CQ (By CPCT)
Hence, Proved.
hope it will help you
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