Question

ABCD is a quadrilateral in which B is 10° more than A. Also D is double of B, and C is
double of A. Find the four angles of the quadrilateral.​

Answer 1

Answer:

LET A BE X

B=X+10°

C=2A =2X

D=2B i.e 2(X+10°)

SINCE SUM OF ALL ANGLES OF A QUAD=360° SO,

X+(X+10)+2X+2(X+10)=360°

X+X+10+2X+2X+20=360

6X+30=360

6X=330

X=55°

angle A=55°, B=65°, C=110°, D=130°