ABCD is a quadrilateral in which B is 10° more than A. Also D is double of B, and C is
double of A. Find the four angles of the quadrilateral.
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Answered by
1
Step-by-step explanation:
according to question
B=10+A
D=2B
C=2A
we know that in a quadrilateral sum of all angles is equal to 360
so,
A+B+C+D=360
A + (10+A) + 2A + 2(10+A) = 360
A + 10 + A + 2A + 20 + 2A = 360
6A + 30 = 360
A + 5 = 60
implies
A=55°
B=10 + A
= 65°
C=2A
=110°
D=2B
=130°
Answered by
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