ABCD is a quadrilateral in which diagonal AC = 84 cm; DL parellel AC, BM parellel AC, DL = 16.5 cm and BM = 12 cm. Find the area of quadrilateral ABCD.
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16
Step-by-step explanation:
area of triangle adm = 1/2×b ×h
1/2×24×7=84sq cm
area of triangle abc = 1/2×b×h
=1/2×24×8=96sq cm
therefore area of quadrilateral abcd=a(adm)+a(abc)
=84+96
=180sqcm
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18
Answer:
Area of quadrilateral ABCD = 504 + 693 = 1197 cm^2
hope it helps u :-)
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