Question

ABCD is a quadrilateral in which diagonal AC is equal to 84 cm, DL perpendicular to AC, BM is perpendicular to AC, DL is equal to 14.2 centimeter and BM supposed to 5.8cm find the area of the quadrilateral​

Answer 1

Therefore the area of the quadrilateral is =840 cm²

Step-by-step explanation:

ABCD is a quadrilateral in which diagonal AC is equal to 84 cm , DL perpendicular to AC , BM is perpendicular to to AC , DL = 14.2 cm and

BM = 5.8 cm.

The diagonal cuts the quadrilateral into two triangle having the same base AC.

The area of a triangle =$=\frac{1}{2}\times base \times height$

Therefore the area of the quadrilateral is

= area ofΔ ABC+area of ΔACD

$=(\frac{1}{2}\times 84 \times 5.8 + \frac{1}{2}\times 84 \times14.2)$ cm²

$=\frac{1}{2}\times 84 (5.8+14.2)$ cm²

=840 cm²

Answer 2

Answer:

840cm square is the right answer

mark me as brain list