Question

. ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that:
(i) SR || AC and SR = 1/2 AC
(ii) PQ = SR
(iii) PQRS is a parallelogram.

Answer 1

Step-by-step explanation:

(I) SR=1/2AC (By mid point theorem ) and SR||AC and

(ii) PQ=1/2AC(By mid point theorem) and PQ||AC

therefore PQ=SR

(iii) PS=1/2BD(By mid point theorem) and PS||BD

QR=1/2BD(By mid point theorem)and QR||BD

As, SR=PQ and PS = QR it is a parallelogram .

Hope it's helpful

Answer 2

Answer:

Step-by-step explanation:

(i) In ΔDAC,

R is the mid point of DC and S is the mid point of DA.

Thus by mid point theorem, SR || AC and SR = ½ AC

(ii) In ΔBAC,

P is the mid point of AB and Q is the mid point of BC.

Thus by mid point theorem, PQ || AC and PQ = ½ AC

also, SR = ½ AC

, PQ = SR

(iii) SR || AC ———————- from question (i)

and, PQ || AC ———————- from question (ii)

⇒ SR || PQ – from (i) and (ii)

also, PQ = SR

, PQRS is a parallelogram.

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