Hindi, asked by 9061742040066, 5 months ago

ABCD is a quadrilateral. P and Q are the mid-points of sides CD and AB respectively. AP and
DQ meet at X whereas BP and CQ meet at Y. Prove that area of AADX + area of ABCY =
area of quadrilateral PXQY.​

Answers

Answered by purnimamandal806
0

Sorry I can't understand the question

Explanation:

This is from which chapter and you read in which class

can you

Answered by bkupadhyay
1

in the give figure find the area of A1+A4+A2+A5=1/2AQ(h1+h2)

A4+A3+A5=1/2 2AQ h3

subtracting we get A1+A2-A3=0

since h3=(h1+h2)/2

from the properties of a trapezium

line joining the mid points of non parallel side is this

Attachments:
Similar questions