ABCD is a quadrilateral. P and Q are the mid-points of sides CD and AB respectively. AP and
DQ meet at X whereas BP and CQ meet at Y. Prove that area of AADX + area of ABCY =
area of quadrilateral PXQY.
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Sorry I can't understand the question
Explanation:
This is from which chapter and you read in which class
can you
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in the give figure find the area of A1+A4+A2+A5=1/2AQ(h1+h2)
A4+A3+A5=1/2 2AQ h3
subtracting we get A1+A2-A3=0
since h3=(h1+h2)/2
from the properties of a trapezium
line joining the mid points of non parallel side is this
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