ABCD is a quadrilateral. P and Q are the mid-points of sides CD and AB respectively. AP and
DQ meet at X whereas BP and CQ meet at Y. Prove that area of AADX + area of ABCY =
area of quadrilateral PXQY.
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Step-by-step explanation:
Given In a parallelogram ABCD, P and Q are the mid-points of AS and CD, respectively.
To show PRQS is a parallelogram.
Proof Since, ABCD is a parallelogram.
AB||CD
⇒ AP || QC
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Answer:
Step-by-step explanation:
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