Question

ABCD is a quadrilateral.Prove that
(I)AC-BC<AB
(II)AC-AD<CD
(III)AB+BC+CD+AD>2AC​

Answer 1

Answer:

use triangles inequality property

1. ac - bc <.ab are false because sum of two angle bigger then 3rd side questions two bhi same hi hai and third Is different

3. ab + bc + cd+ ad > 2ac

the sum of two side is greater then third so proved yes

Step-by-step explanation:

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