ABCD is a quadrilateral such that AD = DC = CA = 20 units, BC = 12 units and ZABC = 90% What is the area of the quadrilateral ABCD?
(Use √3= 1.73)
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Answer:
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Step-by-step explanation:
By applying heron's formula in triangle ABC having the sides 7 cm,6 cm and 9 cm, we have
s=
2
7+6+9
=11 cm
Area of triangle =
s(s−a)(s−b)(s−c)
=
11(11−7)(11−6)(11−9)
=
440
cm
2
Now, in triangle ADC having sides 15 cm,12 cm and 9 cm, we have
s=
2
15+12+9
=18 cm
=
18(18−15)(18−12)(18−9)
=54 cm
2
There, the area of quadrilateral ABCD=(
440
+54) cm
2
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