ABCD is a Quadrilateral such that all of its
sides touch a circle. If
AB = 6cm, BC = 6.5cm and CD = 7cm then the length of ad is
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Answer:
AD = 6.5 cm
Step-by-step explanation:
Let P,Q,R and S be the points where the circle touches the quadrilateral. We know that the lengths of the two tangents drawn from an exterior point to a circle are equal.
Thus, we have, AP=AS,BP=BQ,CR=CQ and DR=DS.
Hence, AP+BP+CR+DR=AS+BQ+CQ+DS
⇒AB+CD=AD+BC.
⇒AD=AB+CD−BC
=6+7−6.5=6.5
Thus, AD=6.5 cm.
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