Question

ABCD is a quadrilateral such that angle A=(4y+20) degree,angle B=(3y-5)degree,angleC=(4x)degree and angleD=(7x+5)degree. Find the four angles

Answer 1

Step-by-step explanation:

as we know that,

=angle A +angle B+angle C+angle D=180°

so,

(4y+20) +(3y-5)+(4x) +(7x+5) =180°

y-5(4+4)+(3-1)+x[4+(7+5)]=180°

y-5(8+2)+x(4+12)=180°

(y-5*10)+(x*16)=180°

10y-50+16x=180°

10y+16x=180+50

y+16x=230/10

y=23-16x __________(i)

keeping the value of y,

{[(4*23)-16x] +20}+{[(3*23)-16x]-5}+(4x) +(7x+5) =180°

(92-16x+20) +(69-16x-5) +(4x) +(7x+5) =180°

[(72-16x) +(64-16x) ]+(4x)+(7x+5) =180°

{16-4x[(6-4)+(4-4) ]}+(4x) +(7x+5) =180°

[16-4x(10) ]+(4x) +(7x+5) =180°

(160-40x) +(4x) +(7x+5) =180°

and now u can find all angles

Thanks